Can I script the program to run again with arguments from a text file?
My question is: I have a program written in C and running it. I use
./program.exe var_1 ... var_n
where var_i-th are both numeric values and strings (used as filenames). I need the program to execute many times with different var_i-th values and every time I had to call the above command.
Is there a way to prepare a .txt file (or something similar) like
- ./program.exe var_1 ... var_n #configuration one
- ...
- ...
- ./program.exe var_1 ... var_n #configuration N
and make the program work with that so that in one call I run all the configurations one by one?
thank
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Create a text file ( foo.sh
for example) with this content, make it executable ( chmod u+x foo.sh
) and run it with ./foo.sh
:
#/bin/bash
/program.exe var_1 ... var_1 #configuration one
/program.exe var_1 ... var_2 #configuration two
/program.exe var_1 ... var_3 #configuration three
.
.
.
./program.exe var_1 ... var_n #configuration N
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To read each line in an array of strings and pass that array to a program, the methods described in BashFAQ # 1 can be used :
while read -r -a args; do
./program.exe "${args[@]}"
done <in.txt
will read arguments from in.txt
, expecting them to be separated by spaces. It will not follow quotes or escape sequences as syntactically significant.
The caveat is that if your file contains:
arg1 "argument two" 13
You'll get:
./program.exe 'arg1' '"argument' 'two"' '13'
... for just four arguments.
If you need quotes to be followed, we'll return to space with xargs
, but with one call per input line:
while read -r line; do
xargs ./program.exe <<<"$line"
done <in.txt
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