Std :: bitset hash functions
Does anyone know what algorithm is using the hash function for the bitset,
this is from the site: http://en.cppreference.com/w/cpp/utility/bitset/hash
#include <iostream>
#include <bitset>
#include <functional>
int main()
{
std::bitset<4> b1(1);
std::bitset<4> b2(2);
std::bitset<4> b3(b2);
std::bitset<4> b4(8);
std::cout<<b4<<'\n';
std::hash<std::bitset<4>> hash_fn;
size_t h1 = hash_fn(b1);
size_t h2 = hash_fn(b2);
size_t h3 = hash_fn(b4);
std::cout << h1 << '\n';
std::cout << h2 << '\n';
std::cout << h3 << '\n';
}
and the output is
1000 4334672815104069193 16667047557902998627 2258353126044249582
http://en.cppreference.com/w/cpp/utility/bitset/hash
Also why doesn't it convert the bits to unsigend long and generate a hash value?
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As Igor pointed out , the C ++ standard does not specify an algorithm, it only requires that the hash value depends only on the object and will be the same for the duration of the program: http://eel.is/c++draft/hash.requirements
20.5.3.4 Hash requirements [hash.requirements] 1 Type H meets the hash requirement if:
- (1.1) this is the type of the function object,
- (1.2) it meets the requirements of CopyConstructible and Destructible, and
- (1.3) the expressions shown in Table 29 are valid and have the specified semantics.
2 This key is an argument type for function objects of type H, in Table 29 h is a value of type (possibly const) H, u is a value of type l of type Key, and k is a value of a type that is converted to (possibly const).
Table 29 - Hashing Requirements
- expression Return type Requirement
- h (k) size_t The return value will only depend on the k argument for the duration of the program. [Note: Thus, all evaluating expression h (k) with the same value for k gives the same result for a when the program runs. - end note] [Note: for two different values โโof t1 and t2, the probability that h (t1) and h (t2) are comparable to equal should be very small, approaching 1.0 / numeric_limits :: max (). - end note]
- h (u) size_t Do not change u.
Gcc libstdc ++ bit implementation uses std :: hash: https://github.com/gcc-mirror/gcc/blob/master/libstdc%2B%2B-v3/include/debug/bitset
#if __cplusplus >= 201103L
// DR 1182.
/// std::hash specialization for bitset.
template<size_t _Nb>
struct hash<__debug::bitset<_Nb>>
: public __hash_base<size_t, __debug::bitset<_Nb>>
{
size_t
operator()(const __debug::bitset<_Nb>& __b) const noexcept
{ return std::hash<_GLIBCXX_STD_C::bitset<_Nb>>()(__b._M_base()); }
};
#endif
// DR 1182.
/// std::hash specialization for bitset.
template<size_t _Nb>
struct hash<_GLIBCXX_STD_C::bitset<_Nb>>
: public __hash_base<size_t, _GLIBCXX_STD_C::bitset<_Nb>>
{
size_t
operator()(const _GLIBCXX_STD_C::bitset<_Nb>& __b) const noexcept
{
const size_t __clength = (_Nb + __CHAR_BIT__ - 1) / __CHAR_BIT__;
return std::_Hash_impl::hash(__b._M_getdata(), __clength);
}
};
LLVM libcxx uses its own implementation for bitset, xoring all words: https://github.com/llvm-mirror/libcxx/blob/2c4b8af9aada61d83610330416eb8a39a8aa5494/include/bitset#L417
template <size_t _Size>
struct _LIBCPP_TEMPLATE_VIS hash<bitset<_Size> >
: public unary_function<bitset<_Size>, size_t>
{
_LIBCPP_INLINE_VISIBILITY
size_t operator()(const bitset<_Size>& __bs) const _NOEXCEPT
{return __bs.__hash_code();}
};
template <size_t _N_words, size_t _Size>
inline
size_t
__bitset<_N_words, _Size>::__hash_code() const _NOEXCEPT
{
size_t __h = 0;
for (size_type __i = 0; __i < _N_words; ++__i)
__h ^= __first_[__i];
return __h;
}
and a simpler option for a 1-bit set of words:
inline
size_t
__bitset<1, _Size>::__hash_code() const _NOEXCEPT
{
return __first_;
}
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