Clever Geek Handbook

Python read binary byte by byte

This may sound pretty silly, but I am a complete newbie to python.

So, I have a binary starting with

ff d8 ff e0 00 10 4a

(as shown both via Hex Editor Neo and in java program)

but when i tried to read it using python

with open(absolutePathInput, "rb") as f:
    while True:
        current_byte = f.read(1)
        if(not current_byte):
            break
        print(hex(current_byte[0]))

I get

ff d8 ff e0 0 10 31

This seems to be going wrong when the first 0x00 is read.

what am I doing wrong? Thank u!

+3


source to share


2 answers


I think the problem is that you are trying to play out current_byte as if it were an array, but it is just a byte

def test_write_bin(self):  
  fname = 'test.bin'
  f = open(fname, 'wb')
  # ff d8 ff e0 00 10 4a
  f.write(bytearray([255, 216, 255, 224, 0, 16, 74]))
  f.close()
  with open(fname, "rb") as f2:
    while True:
      current_byte = f2.read(1)
      if (not current_byte):
        break
      val = ord(current_byte)
      print hex(val),
  print


This program produces output:

0xff 0xd8 0xff 0xe0 0x0 0x10 0x4a
+1


source 


import binascii

with open(absolutePathInput, "rb") as f:
    buff = f.read()

line = binascii.hexlify(buff)
hex_string = [line[i:i+2] for i in range(0, len(line), 2)]


simple and cruel

0


source






More articles:


All Articles