Clever Geek Handbook

C ++ for selecting two random numbers from a range with minimum distance

I have a std :: vector initialized with numbers from 1 to 100

std::vector<int> vec;
for(int i = 1; i < 101; i++)
  vec.push_back(i);

I want to select two random numbers that have a minimum distance (for example, the minimum distance might be 10).

If num1, num2 are numbers:

num2 - num1> distance

I am using the following method to select a random integer between ranges:

int getRandomValue(int from, int to)
        {
                std::random_device seeder;
                std::mt19937 engine(seeder());
                std::uniform_int_distribution<int> dist(from, to);
                return dist(engine);
        }

How can I generate num2 and num1?

+3


source to share


3 answers


You can use something like the following:

num1 = getRandomValue(minRange, maxRange - distance - 1);
num2 = getRandomValue(num1 + distance + 1, maxRange);


Note that this would not be an even distribution for the pair result.

+4


source


you can randomize num1 for example and sum the distance, then you have num2.

But you have to be careful, the reason num1 must be below or equal to 100-distance



or oposite randomize num2 from 10 to 100 and num1 = num2-distance

0


source 


#include <cstdlib>

a = rand() % 90;
b = a + 10;

a less, b more [/ p>

0


source






More articles:


All Articles