Eliminating the error "expression must have a pointer to the class type"

Question

class testClass { public: int B, C; };

testClass u;
testClass * k = &u;
testClass ** m = &k;

*m->B = 1;//Error appears here

I think I followed the pointer rules correctly. I still don't know why this is happening. Can anyone help me?

+3

c ++ pointers operator-precedence

hexcode 07 June '17 at 3:50

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1 answer

songyuanyao · Accepted Answer · 2017-06-07T03:52:52+0000

operator->

has a higher precedence than operator*

, therefore *m->B

equivalent to *(m->B)

; and m->B

is invalid here.

You must change it to (*m)->B

.