Checkbox does not print to console
I am new to flask and I am trying to add print information to debug server side code. When running the app with a flag with debug = True, I cannot get any printable information to the console
I tried to use the recording but no luck. So, how to debug the console flask.
@app.route('/getJSONResult', methods=['GET', 'POST'])
def getJSONResult():
if request.method == 'POST':
uut = request.form['uut']
notes = request.form['notes']
temperature = request.form['temperature']
logging.info("enter getJSONReuslt")
print('enter getJSONReuslt')
filter_by_query = {k: v for k, v in {
'uut': uut, 'notes': notes, 'temperature': temperature}.items() if v != ""}
s = session.query(UUT_TEST_INFO).filter_by(**filter_by_query).first()
return jsonify(s.serialize)
if __name__ == '__main__':
app.secret_key = ''.join(random.choice(
string.ascii_uppercase + string.digits) for x in range(32))
app.debug = True
app.run(host='127.0.0.1', port=5000)
> 127.0.0.1 - - [07/Jun/2017 15:20:48] "GET /qyer HTTP/1.1" 200 -
> 127.0.0.1 - - [07/Jun/2017 15:20:48] "GET /static/css/bootstrap.min.css HTTP/1.1" 200 -
> 127.0.0.1 - - [07/Jun/2017 15:20:48] "GET /static/js/bootstrap.min.js HTTP/1.1" 200 -
> 127.0.0.1 - - [07/Jun/2017 15:20:51] "GET /static/css/bootstrap.min.css.map HTTP/1.1" 200 -
> 127.0.0.1 - - [07/Jun/2017 15:21:58] "POST /getJSONResult HTTP/1.1" 500 -
I fixed a 500 server side error, now ask for code 200 and the console will show the following information
$ python project.py
INFO:werkzeug: * Running on http://127.0.0.1:5000/ (Press CTRL+C to quit)
INFO:werkzeug: * Restarting with stat
WARNING:werkzeug: * Debugger is active!
INFO:werkzeug: * Debugger pin code: 158-624-607
INFO:werkzeug:127.0.0.1 - - [08/Jun/2017 11:33:33] "GET /qyer HTTP/1.1" 200 -
INFO:root:Enter getJSONResult
INFO:werkzeug:127.0.0.1 - - [08/Jun/2017 11:33:43] "POST /getJSONResult HTTP/1.1" 200 -
Still no information from print command
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Try this and see if it helps:
For python2:
from __future__ import print_function
import sys
print('This is error output', file=sys.stderr)
print('This is standard output', file=sys.stdout)
For python3, you don't need to import from the future print_function:
import sys
print('This is error output', file=sys.stderr)
print('This is standard output', file=sys.stdout)
See if this helps for printing to the console.
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You can forcefully flush standard output from printing:
print('enter getJSONReuslt', flush=True)
This way you don't have to type in sys.stderr
(which is reset by default).
Linear buffering is causing your problem. Linear buffering makes I / O more efficient, with the disadvantage of immediately displaying fingerprints under certain conditions.
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