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Purrr :: map is equivalent to dplyr :: do

Reading https://twitter.com/hadleywickham/status/719542847045636096 I understand that the approach purrr

should basically replace do

.

Hence, I was wondering how I would use purrr

for this:

library(dplyr)
d <- data_frame(n = 1:3)
d %>% rowwise() %>% do(data_frame(x = seq_len(.$n))) %>% ungroup()
# # tibble [6 x 1]
#       x
# * <int>
# 1     1
# 2     1
# 3     2
# 4     1
# 5     2
# 6     3

The closest I could get was something like:

library(purrrr)
d %>% mutate(x = map(n, seq_len))
# # A tibble: 3 x 2
#       n         x
#   <int>    <list>
# 1     1 <int [1]>
# 2     2 <int [2]>
# 3     3 <int [3]>

map_int

does not work. So what is the way purrrr

to do this?

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2 answers


You can do the following:

library(tidyverse)
library(purrr)
d %>% by_row(~data_frame(x = seq_len(.$n))) %>% unnest()


by_row

applies the function to each line, keeping the result in nested ties. unnest

then used to remove nesting and to concatenate tibles.

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Usage pmap()

eliminates the need for nesting and deletion.



library(tidyverse)
d %>% pmap_df(~data_frame(x = seq_len(.)))
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