How do I convert my data to small format?
4 answers
let value = UInt16(bigEndian: 1500)
print(String(format:"%04X", value.bigEndian)) //05DC
print(String(format:"%04X", value.littleEndian)) //DC05
Make sure you are using an initializer bigEndian
.
With 32-bit integers:
let value = UInt32(bigEndian: 1500)
print(String(format:"%08X", value.bigEndian)) //000005DC
print(String(format:"%08X", value.littleEndian)) //DC050000
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If you want 1500 as a byte array in order of order:
var value = UInt32(littleEndian: 1500)
let array = withUnsafeBytes(of: &value) { Array($0) }
If you want it like Data
:
let data = Data(array)
Or, if you really wanted it to be a hex string:
let string = array.map { String(format: "%02x", $0) }.joined()
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You can do something like
//: Playground - noun: a place where people can play
import UIKit
extension String {
func hexadecimal() -> Data? {
var data = Data(capacity: count / 2)
let regex = try! NSRegularExpression(pattern: "[0-9a-f]{1,2}", options: .caseInsensitive)
regex.enumerateMatches(in: self, range: NSRange(location: 0, length: utf16.count)) { match, _, _ in
let byteString = (self as NSString).substring(with: match!.range)
var num = UInt8(byteString, radix: 16)!
data.append(&num, count: 1)
}
guard !data.isEmpty else { return nil }
return data
}
}
func convertInputValue<T: FixedWidthInteger>(_ inputValue: Data) -> T where T: CVarArg {
let stride = MemoryLayout<T>.stride
assert(inputValue.count % (stride / 2) == 0, "invalid pack size")
let fwInt = T.init(littleEndian: inputValue.withUnsafeBytes { $0.pointee })
let valuefwInt = String(format: "%0\(stride)x", fwInt).capitalized
print(valuefwInt)
return fwInt
}
var inputString = "479F"
var inputValue: Data! = inputString.hexadecimal()
let val: UInt16 = convertInputValue(inputValue) //9F47
inputString = "479F8253"
inputValue = inputString.hexadecimal()
let val2: UInt32 = convertInputValue(inputValue) //53829F47
0
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