Python - function class
def Func():
pass
In an IPython session, when you type (Func), the output is a "function". Since Python is an object oriented language, I am assuming there is a class that "Func" is an instance of. So I tried to create my own class like this:
class MyFunc(function):
pass
Alas, the interpreter just threw a "NameError", complaining that the "function" was undefined. So, I tried to be a little smart and did this:
class myfunc(func.__class__):
pass
Alas, this failed miserably ...
TypeError: Error when calling the metaclass bases
type 'function' is not an acceptable base type
In general, someone can explain: 1). How to create a class derived from a "function" type. If this is not possible, why? 2). This message really meant.
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In general, someone can explain: 1). How to create a class derived from a "function" type.
You can not.
If this is not possible, why? 2). This message really meant.
This error message means that Python will not allow classes to use the function type as a base class. Classes implemented in C can only be extended if they set a specific flag; if they don't, this is the error you get when you try to expand them.
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