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Digits with numbers from 1 to 100 and every 10 numbers keep the division of the number by 10

This code does what I want, but I think there is a better charm that this code could do in multiple lines, especially if the loop is from 1 to 1000

for ($i=1; $i <= 100; $i++) 
{
    if ($i <= 10 ) {
        $id = 1;
    }
    elseif ($i > 10 && $i <= 20) {
        $id = 2;
    }
    elseif ($i > 20 && $i <= 30) {
        $id = 3;
    }
    elseif ($i > 30 && $i <= 40) {
        $id = 4;
    }
    elseif ($i > 40 && $i <= 50) {
        $id = 5;
    }
    elseif ($i > 50 && $i <= 60) {
        $id = 6;
    }
    elseif ($i > 60 && $i <= 70) {
        $id = 7;
    }
    elseif ($i > 70 && $i <= 80) {
        $id = 8;
    }
    elseif ($i > 80 && $i <= 90) {
        $id = 9;
    }
    elseif ($i > 90 ) {
        $id = 10;
    }

    $array = ['id' => $id, 'order' => $i];

    Provider::create($array);
}
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2 answers


Here's your solution:



for ($i=1; $i <= 1000; $i++) 
{
    $id = ceil($i/10);
    $array = ['id' => $id, 'order' => $i];

    Provider::create($array);
}
+2


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Use the code below:

<?php
$arr = array();
for ($i=1; $i <= 100; $i++) 
{
    $id = $i/10;
    if ($i%10 == 0) {
      echo "id: ".$id." Order: ".$i."\n";
      $arr[$id] = $i;
    }
}
print_r($arr);

Output



id: 1 Order: 10
id: 2 Order: 20
id: 3 Order: 30
id: 4 Order: 40
id: 5 Order: 50
id: 6 Order: 60
id: 7 Order: 70
id: 8 Order: 80
id: 9 Order: 90
id: 10 Order: 100
Array
(
    [1] => 10
    [2] => 20
    [3] => 30
    [4] => 40
    [5] => 50
    [6] => 60
    [7] => 70
    [8] => 80
    [9] => 90
    [10] => 100
)

Demo: Click here

+1


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