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Selecting all XML elements and their values ​​dynamically using LINQ

I have the following code that dynamically selects all individual item names; I also want to see the values ​​for these elements. How can I do this using LINQ? I am open to this in other ways as well.

 XDocument doc = XDocument.Load("XMLFile1.xml");
 foreach (var name in doc.Descendants("QueryResults").Elements()
                .Select(x => x.Name).Distinct())
 {
 }
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3 answers


Something like this will work



   XDocument doc = XDocument.Load("XMLFile1.xml");
   foreach (var name in doc.Descendants("QueryResults").Elements()
                .Select(x => new {Name = x.Name, Value = e.Value}).Distinct())
   {


   }
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The accepted query is different from the original one because it changes the way it works Distinct

, because it no longer only compares Name

as well Value

. If you want to see what names have values ​​that you need to use GroupBy

in Name

and get Value

for each item.



var results =
    doc
        .Descendants("QueryResults")
        .Elements()
        .GroupBy(x => x.Name, (name, items) => new
        {
            Name = name,
            Values = items.Select(x => x.Value)
        });
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You would just use name.Value

that is a string property XElement

.

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