How do I run a fixture twice in a test case using pytest?

Here I am using this device to create obj network with iprange. Although in some cases I need to create 2 different networks in one test.

@pytest.fixture(scope="function")
def fixture_user_create_network_with_iprange(get_user_token,
                                          fixture_user_create_network,
                                          fixture_user_create_iprange,
                                          request):
    token = get_user_token
    network_uuid = fixture_user_create_network
    iprange_uuid = fixture_user_create_iprange
    add_ipranges_to_networks(token,network_uuid,iprange_uuid)

    return network_uuid

      

But in the same test, the device can only work once. I am creating another device named , this is a copy of the original device, but a different name.fixture_user_create_

2nd

_network_with_iprange

Interaction with these 2 devices are also used fixture_user_create_network

, fixture_user_create_iprange

which are executed only once in the test. I only have one obj network.

So I want to know

  • if I can get the appliances to work twice in the test, or
  • if I can call the device at any time in a test case on demand.
+3


source to share


2 answers


You cannot start one device twice. This is contrary to the concept of luminaires.

However, you can extract network_uuid

into a function (function only) and declare 2+ fixtures that call it.

You can also call lights dynamically:

@pytest.fixture
def fixt1(request):
    return 'hello'

@pytest.fixture
def fixt2(request):
    return request.getfuncargvalue('fixt1')

def test_me(fixt2):
    assert fixt2 == 'hello'

      

But still, only once per test.



If you want a dynamic number of similar fixtures, you can generate them:

import pytest

# Just for proper var closures:
def _make_fixt_fn(i):
    @pytest.fixture
    def fixt_fn(....):
        return 'fixt{}'.format(i)
    return fixt_fn

# The fixtures must reside in the module namespace. The decorator is just a mark.
for i in range(1, 4):
    name = 'dyn_fixt_{}'.format(i)
    global()[name] = _make_fixt_fn(i)

def test_dyn(dyn_fixt_1, dyn_fixt_2, dyn_fixt_3):
    pass

      

Lets check:

$ pytest test_dyn.py --fixtures
...
------- fixtures defined from test_dyn ----------
dyn_fixt_1
    test_dyn.py:6: no docstring available
dyn_fixt_2
    test_dyn.py:6: no docstring available
dyn_fixt_3
    test_dyn.py:6: no docstring available

      

0


source


You can use mark.parametrize with an "indirect" switch to allow a power parameter to be passed to your fixture and then simply return that number of copies:



@pytest.fixture
def data_repeated(request):
    return [deepcopy({'a': 1, 'b': 2}) for _ in range(request.param)]


@pytest.mark.parametrize('data_repeated', [3], indirect=['data_repeated'])
def test(data_repeated):
    assert data_repeated == [
        {'a': 1, 'b': 2},
        {'a': 1, 'b': 2},
        {'a': 1, 'b': 2}]

      

0


source







All Articles