How to wait for an object to change.

Inside the handler, async

I want to wait for the task state to change. For now, I just check the state in an infinite loop and wait. Here's an example, a function wait_until_done

:

import asyncio


class LongTask:
    state = 'PENDING'

my_task = LongTask()


def done():
    my_task.state = 'DONE'

async def wait_until_done():
    while True:
        if my_task.state == 'PENDING':
            await asyncio.sleep(2)
        else:
            break
    print("Finally, the task is done")


def main(loop, *args, **kwargs):
    asyncio.ensure_future(wait_until_done())
    loop.call_later(delay=5, callback=done)

loop = asyncio.get_event_loop()
main(loop)
loop.run_forever()

      

Is there a better way to do this?

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2 answers


Just to avoid confusion: I guess you are not talking about asyncio.Task , but some kind of state variable instead ?? //>

In this case, you are Future and synchronization primitives , which allows you to wait for some thing to change asynchronously.

If you need to switch between two states, asyncio.Event is probably what you want. Here's a small example:

import asyncio


my_task = asyncio.Event()


def done():
    my_task.set()



async def wait_until_done():
    await my_task.wait()  # await until event would be .set()
    print("Finally, the task is done")


async def main():
    loop.call_later(delay=5, callback=done)
    await wait_until_done()


loop = asyncio.get_event_loop()
try:
    loop.run_until_complete(main())
finally:
    loop.run_until_complete(loop.shutdown_asyncgens())
    loop.close()

      



Upd:

A more complex example that supports the interface LongTask

:

import asyncio



class LongTask:
    _event = asyncio.Event()

    @property
    def state(self):
        return 'PENDING' if not type(self)._event.is_set() else 'DONE'

    @state.setter
    def state(self, val):
        if val == 'PENDING':
            type(self)._event.clear()
        elif val == 'DONE':
            type(self)._event.set()
        else:
            raise ValueError('Bad state value.')

    async def is_done(self):
        return (await type(self)._event.wait())

my_task = LongTask()


def done():
    my_task.state = 'DONE'



async def wait_until_done():
    await my_task.is_done()
    print("Finally, the task is done")


async def main():
    loop.call_later(delay=5, callback=done)
    await wait_until_done()


loop = asyncio.get_event_loop()
try:
    loop.run_until_complete(main())
finally:
    loop.run_until_complete(loop.shutdown_asyncgens())
    loop.close()

      

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Isn't this a sample Observer design pattern? I think the Observer pattern can solve this problem. In this design pattern, we don't have to iterate endlessly to detect a change, but the task itself will tell you if it has made any changes. A simple implementation could be:

class ObservableTask:
    def __init__(self):
        self.subscribers = set()
        self.state = 'PENDING'

    def subscribe(self, who):
        self.subscribers.add(who)

    def unsubscribe(self, who):
        self.subscribers.discard(who)

    def dispatch(self, message):
        for subscriber in self.subscribers:
            subscriber.update(message)

    def random_change(self):
        for count in range(1, 10):
            if count % 5 == 0:
                print('Inside task:\tDivisible by 5')
                self.state = 'DONE'
                self.dispatch('state: DONE')


class Observer:
    def __init__(self):
        pass

    def update(self, message):
        print('Task is changed!\t' + message)


# Test:
task = ObservableTask()
observer = Observer()

task.subscribe(observer)
task.random_change()

      



Output:

Inside task:    Divisible by 5
Task is changed!    state: DONE

      

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