Get first and second values in a dictionary in CPython 3.6
Now that the dictionaries are ordered in python 3.6 it should be that there is a way to get the first and second values of the dictionary in just two lines. Right now, I have to use 7 lines to accomplish this:
for key, value in class_sent.items():
i += 1
if i == 1:
first_sent = value
elif i == 2:
second_sent = value
I've also tried:
first_sent = next(iter(class_sent)) second_sent = next(iter(class_sent))
But in this case, second_sent is equal to first_sent. If anyone knows how to get the first and second values in a dictionary in as few lines as possible, I would seriously appreciate it.
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2 answers
Right now Python only guarantees that the order **kwargs
and attributes of the class are preserved .
Considering the Python implementation you are using guarantees the kind of behavior you could do.
- Use
itertools.islice
.
>>> from itertools import islice
>>> dct = {'a': 1, 'b': 2, 'c': 3}
>>> first, second = islice(dct.values(), 2)
>>> first, second
(1, 2)
- Use
iter()
.
>>> it = iter(dct.values())
>>> first, second = next(it), next(it)
>>> first, second
(1, 2)
- Using advanced iterative unboxing (will result in unnecessary unboxing of other values):
>>> first, second, *_ = dct.values()
>>> first, second
(1, 2)
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