Python regex re.search to list

I have some code to parse linux 'df -h', normal command line output looks like this:

Filesystem      Size  Used Avail Use% Mounted on
udev            987M     0  987M   0% /dev
tmpfs           201M  9.2M  191M   5% /run
/dev/sda1        38G   11G   25G  30% /
tmpfs          1001M  416K 1000M   1% /dev/shm
tmpfs           5.0M     0  5.0M   0% /run/lock
tmpfs          1001M     0 1001M   0% /sys/fs/cgroup
tmpfs           201M   28K  201M   1% /run/user/132
tmpfs           201M   28K  201M   1% /run/user/0

      

        
        
        
      

    

Currently my code is achieving the desired output:

['/run', '/run/lock', '/run/user/132', '/run/user/0']

      

        
        
        
      

    

But the line print ([x.split (") [- 1] for x in newlist]) shown below looks like a hack, I am struggling to get this to work as a regex using the 'r. Search for" below can Anyone suggest a better way to do this please?

import subprocess
import re


cmd = 'df -h'
output = subprocess.check_output(cmd, shell=True).decode('utf8')
ln = output.split('\n')
r = re.compile('/run.*')
newlist = list(filter(r.search, ln))

print ([x.split(" ")[-1] for x in newlist])

      

        
        
        
      

    

Edit * I'm using 'df -h' as ​​some random output for a regex, so when @romanPerekhrest suggests the best real world solution for this problem, I looked for a regex solution.