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How do I crop a UIView like a semicircle?

I want to crop a UIView to a semicircle shape

like this picture

Thanks in advance.

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2 answers


A convenient way is to just subclass a UIView

, add a layer to it and make the view color transparent if not the default.



import UIKit

class SemiCirleView: UIView {

    var semiCirleLayer: CAShapeLayer!

    override func layoutSubviews() {
        super.layoutSubviews()

        if semiCirleLayer == nil {
            let arcCenter = CGPoint(x: bounds.size.width / 2, y: bounds.size.height / 2)
            let circleRadius = bounds.size.width / 2
            let circlePath = UIBezierPath(arcCenter: arcCenter, radius: circleRadius, startAngle: CGFloat.pi, endAngle: CGFloat.pi * 2, clockwise: true)

            semiCirleLayer = CAShapeLayer()
            semiCirleLayer.path = circlePath.cgPath
            semiCirleLayer.fillColor = UIColor.red.cgColor
            layer.addSublayer(semiCirleLayer)

            // Make the view color transparent
            backgroundColor = UIColor.clear
        }
    }    
}
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This question has already been answered here: Draw iOS semicircle button

This is an excerpt from this question, but using UIView:

Swift 3

let myView = [this should be your view]
let circlePath = UIBezierPath(arcCenter: CGPoint(x: myView.bounds.size.width / 2, y: 0), radius: myView.bounds.size.height, startAngle: 0.0, endAngle: CGFloat(M_PI), clockwise: true)
let circleShape = CAShapeLayer()
circleShape.path = circlePath.cgPath
myView.layer.mask = circleShape

Swift 4



let myView = [this should be your view]
let circlePath = UIBezierPath(arcCenter: CGPoint(x: myView.bounds.size.width / 2, y: 0), radius: myView.bounds.size.height, startAngle: 0.0, endAngle: .pi, clockwise: true)
let circleShape = CAShapeLayer()
circleShape.path = circlePath.cgPath
myView.layer.mask = circleShape

Swift 5

[Soon]

I hope this helps you

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