Split string between characters using python regex
I am trying to split the line:
> s = Ladegårdsvej 8B7100 Vejle
with regex in:
[street,zip,city] = ["Ladegårdsvej 8B", "7100", "Vejle"]
s
varies a lot, the only definite part is that zip always has 4 digits and spaces. So my idea is to "match right" by 4 digits and a space to indicate that the string should be split by that point in the string.
Currently I can get street
and city
like this:
> print re.split(re.compile(r"[0-9]{4}\s"), s)
["Ladegårdsvej 8B", "Vejle"]
How would I go for splitting s
at will; in particular, how do I do it in the middle of the line between the number in street
and zip
?
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You can use re.split
, but make four digits a capture group:
>>> s = "Ladegårdsvej 8B7100 Vejle"
>>> re.split(r"(\d{4}) ", s)
['Ladegårdsvej 8B', '7100', 'Vejle']
From the documentation (emphasis mine)
Split string for presence of patterns. If parentheses are used in the pattern, then the text of all groups in the pattern is also returned as part of the resulting list. If maxsplit is nonzero, maxsplit splits at most, and the rest of the string is returned as the final element of the list.
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Here is the solution to the problem.
# -*- coding: utf-8 -*-
import re
st="Ladegårdsvej 8B7100 Vejle"
reg=r'([0-9]{4})'
rep=re.split(reg,st)
print rep
Solution for other test cases provided by RasmusP_963 sir.
# -*- coding: utf-8 -*-
import re
st="Birkevej 8371900 Roskilde"
print re.split(r"([0-9]{4}) ",st)
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