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Extract all punctuation marks from string in VB.net

How to remove all punctuation marks from a string in vb.net? I really don't want to do stringname.Replace("$", "")

punctuation for every bit, although it will work.

How to do it quickly and efficiently?

Apart from coding the code that encodes this for me ....

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3 answers


You can use a regex to match whatever you want to remove:

str = Regex.Replace(str, "[^A-Za-z]+", String.Empty);


[^...]

- a negative set that matches any character that is not in the set. You can simply add any character you want to keep there.

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A quick example using a positive regex. Just put the characters you want to remove in it:



          Imports System.Text.RegularExpressions
          Dim foo As String = "The, Quick brown fox. Jumped over the Lazy Dog!" 
          Console.WriteLine(Regex.Replace(foo,"[!,.\"'?]+", String.Empty))
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If you want a non-regex you can try something like this:

Dim stringname As String = "^^^%%This,,,... is $$my** original(((( stri____ng."

Dim sb As New StringBuilder
Dim c As Char

For Each c In stringname
    If Not (Char.IsSymbol(c) OrElse Char.IsPunctuation(c)) Then
        sb.Append(c)
    End If
Next

Console.WriteLine(sb.ToString)

Exit " This is my original string

".

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