What would be the correct way to declare an array inside a script that will be called by cron?
I wrote a KornShell (ksh) script that sets up an array like this:
set -A fruits Apple Orange Banana Strawberry
but when i try to run it from inside cron it throws the following error:
Your "cron" job on myhost
/myScript.sh
produced the following output:
myScript.sh: -A: bad option(s)
I've tried many variations of the crontab syntax, for example:
Attempt 1:
0,5,10,15,20,25,30,35,40,45,50,55 * * * * /path/to/script/myScript.sh
Attempt 2:
0,5,10,15,20,25,30,35,40,45,50,55 * * * * /path/to/script/./myScript.sh
Attempt 3:
0,5,10,15,20,25,30,35,40,45,50,55 * * * * cd /path/to/script && ./myScript.sh
Any workaround would be sincerely appreciated. Many thanks!
0
Nano taboada
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3 answers
Although I'm not sure if this is the best way to do it, I managed to solve this problem as follows:
Attempt 4:
0,5,10,15,20,25,30,35,40,45,50,55 * * * * cd /path/to/script && ksh ./myScript.sh
+1
Nano taboada
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*/5 * * * * cd /path/to/script && ksh ./myScript.sh
: - it will run every 5 minutes. Define Path variables also in cron itself.
+3
Mandar pande
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Does it include myScript.sh
with
#!/bin/ksh
(or what would be the path for your ksh)?
+2
cjm
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