Finding the position of an offset client element

How can I find the offset client position of an element using Javascript? (I assume the same code can be written in BHO or Gecko / NPAPI).

The problem I'm running into is the way to determine the position of the biased client. e.srcElement.offsetX/Y

does not always give the correct value (same goes for clientX / Y). In some cases, we also need to consider the scrolling of the parent element.

How do we do it in general? Is there an easy way to do this?

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4 answers


function getElementTop ( Elem ) 
{
    var elem;

    if ( document.getElementById ) 
    {   
        elem = document.getElementById ( Elem );
    } 
    else if ( document.all ) 
    {
        elem = document.all[Elem];
    }           

    yPos = elem.offsetTop;
    tempEl = elem.offsetParent;

    while ( tempEl != null ) 
    {
        yPos += tempEl.offsetTop;
        tempEl = tempEl.offsetParent;
    }  

    return yPos;
}   


function getElementLeft ( Elem ) 
{
    var elem;

    if ( document.getElementById ) 
    {
        var elem = document.getElementById ( Elem );
    } 
    else if ( document.all )
    {
        var elem = document.all[Elem];
    }           

    xPos = elem.offsetLeft;
    tempEl = elem.offsetParent;         

    while ( tempEl != null ) 
    {
        xPos += tempEl.offsetLeft;
        tempEl = tempEl.offsetParent;
    }           
    return xPos;
}

      



Pass the id of the element to the function.

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See the code below:



function getOffsetSum(elem) {
    var top=0, left=0;
    while(elem) {
        top = top + parseInt(elem.offsetTop);
        left = left + parseInt(elem.offsetLeft);
        elem = elem.offsetParent;
    }
    return {top: top, left: left};
}

      

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To enable scrolling, look at this jQuery event listener for registering scrollTop and offset.

// Don't put this in the scroll event listener callback, or that will be unnecessarily performance intensive.
var offset = $("#id").offset().top;

$(window).bind("scroll", function() {

 console.log(
  $(window).scrollTop() + 
  offset
 );

});

      

To get just the offset,

("#id").offset().top;

      

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CoffeeScript version of Orhun Alp Oral's answer :

getOffset = (elem)->
    top = 0
    left = 0
    while elem
        top += parseInt(elem.offsetTop)
        left += parseInt(elem.offsetLeft)
        elem = elem.offsetParent
    {top, left}

      

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