Show current line of executable C code

Is there a way to view the C code "live" by displaying the current current line when it is executed?

You can use GDB quite closely, but I'm wondering if there is something a little more elegant than holding the return key:

$ gdb ./mycode
(gdb) break 1
Breakpoint 1 at 0x100000f08: file mycode.c, line 1.
(gdb) run
Starting program: mycode 

Breakpoint 1, main () at mycode.c:4
4        for(x = 0; x < 4; x++){
(gdb) next
5            printf("Example\n");
(gdb) [press return]
Example
4        for(x = 0; x < 4; x++){
(gdb) [press return]

      

        
        
        
      

    

Performance is not an issue (it will obviously slow down a lot by everyone printf()

'ing, which is good). Ideally the solution would be a command line tool (alternatively, OS X compatible).

Perhaps the use will be carried out line by line ..

$ viewlivec --delay 500 -- ./mycode -mycodes=arg --verbose
01: int main(){
02: int x;
03: for(x = 0; x < 4; x++){
04: printf("Example\n");
05: }
03: for(x = 0; x < 4; x++){
04: printf("Example\n");
05: }
03: for(x = 0; x < 4; x++){
04: printf("Example\n");
05: }
03: for(x = 0; x < 4; x++){
04: printf("Example\n");
05: }
06: }

      

        
        
        
      

    

The flag --delay

will wait 0.5 seconds between each line

(This may have been asked before, but I wasn't sure what to look for, so I couldn't find anything)