What happens first in PHP, includes or parses?
Let's assume there is no byte cache.
Will there be parsing my_func
before including a and b or after?
$x=my_func();
//a.php and b.php are **very** heavy scripts
include ('a.php');
include ('b.php');
//my_func makes the browser use it cached version of the page.
function my_func(){
//send caching headers
//header(....);
exit;
}
source to share
Why don't you give it a try?
For example, you might have the first file named temp.php
that contains the following:
<?php
$a = my_func();
include 'temp-2.php';
function my_func() {
die;
}
And the second file temp-2.php
that will contain this:
<?php
sleep(5);
When you call temp.php
from your web browser, how long does it take for the page to load? Is it almost instantaneous? Or does it take 5 seconds?
In the first case, the function is called before it is enabled temp-2.php
.
... And after trying: it only takes a moment - this means the second file is not included when there is a stamp or exit in the function.
EDIT after comment: Oh sorry, I didn't quite understand the question, I suppose: --(
Here's another try: temp.php
still contains the following:
<?php
$a = my_func();
include 'temp-2.php';
function my_func() {
die;
}
But the file temp-2.php
now only contains this:
<?php
,
Which, yes, you get a parsing error if PHP tries to parse this file.
If you are calling temp.php
from your problem, that doesn't seem to be the problem: nothing is displayed and there is no parsing error.
Now if you comment out the line " die
" inside the function my_func
and try calling it again temp.php
in your browser, you get:
Parse error: syntax error, unexpected ',' in /home/squale/developpement/tests/temp/temp-2.php on line 3
Which indicates a Parse error if PHP tries to parse this second file.
So, the first time the function is called before PHP actually tried to parse the second file.
Hope this answer puts you in a better position, this time :-)
source to share
Basically, the order will be correct. Consider:
a.php:
<?php echo "A\n"; ?>
b.php:
<?php echo "B\n"; ?>
c.php:
<?php
my_func();
include 'a.php';
include 'b.php';
function my_func() {
echo "C\n";
}
?>
The output will be:
C
A
B
But change c.php to:
<?php
my_func();
include 'a.php';
function my_func() {
include 'b.php';
echo "C\n";
}
?>
and the output will change to:
B
C
A
source to share