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Memory location

Can anyone please provide a C code to display all values ​​in a memory location from 0 to the end?

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Assuming you are on a system with no secure memory access and / or no MMU, so the addresses used are true physical addresses, this is really easy.

#include <stdio.h>
#include <stdlib.h>

/* Print memory contents from <start>, 16 bytes per line. */    
static void print_memory(const void *start, size_t len)
{
  const unsigned char *ptr = start;
  int count = 0;

  printf("%p: ", ptr);

  for(; len > 0; --len)
  {
    printf("%02X ", *ptr++);
    if(++count >= 16)
    {
      printf("\n%p: ", ptr);
      count = 0;
    }
  }
  if(count > 0)
    putchar('\n');
}

int main(void)
{
  print_memory(NULL, 1024);

  return EXIT_SUCCESS;
}


This should work fine for example. old Amiga , but little used on modern PCs running Linux, Windows, etc.

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You won't be able to do this, as dereferencing a null location will result in a SEGV signal on all Unix systems except HP-UX, where it depends on the compiler switch or runtime attribute if the null location can be dereferenced.



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The question is a bit vague.

You either want to map all the memory, which won't work (at least not easy) due to the mapping and replacement.

Or you want to map a portion of the allocated memory. It's easy. You can create a pointer to memory and map all the corresponding bytes. Or, if you know the layout, you can create a structure. Either way, you need to know where the end is. Knowing the size or separator symbol.

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