How can I execute an option in the list?
This is a general form, but if you don't know the list at design time, while you can get a link to the node of nodes that represents the list, you can run a simple test like:
<xsl:when test="$listset/item[@property=$variable]">
where the property is $ variable = / foo / bar / @ and $ listset = / foo / list for XML
<?xml version="1.0"?>
<foo>
<bar property="gb" />
<list>
<item property="gb"/>
<item property="us"/>
</list>
</foo>
source to share
Try using xsl: select. (Also see the spec here ) It provides basic if / else functionality. EDIT - I tested and it works:
<xsl:choose>
<xsl:when test="domain = 'GB' or domain = 'US' or domain = 'ES' or domain = 'FR'">
print this html
</xsl:when>
<xsl:otherwise>
print other html
</xsl:otherwise>
</xsl:choose>
source to share
If you are using XSLT 2.0 given file
You can use something like this:
<xsl:template match="list/item">
Property [<xsl:value-of select="@property"/>] html
</xsl:template>
<xsl:template match="list/item[some $x in ('us', 'gb') satisfies $x eq @property ]">
Property [<xsl:value-of select="@property"/>] HTML
</xsl:template>
source to share
Another solution not mentioned by the current 3 answers is to have an options string against which you are comparing the value domain
. Then the following XPath expression (in an attribute @test
like <xsl:if>
or <xsl:when>
evaluates to true()
exactly when the value domain
is one of the delimited values in the string (we use a space for the delimiter in this particular example):
contains(' GB US ES ', concat(' ', domain, ' '))
Here we assume domain
there are no spaces in the value . If this cannot be guaranteed, the XPath expression can also check for this requirement:
not(contains(domain, ' '))
and
contains(' GB US ES ', concat(' ', domain, ' '))
source to share