Stop jQ animation

Question

Stop jQ animation

I got a problem: I don't know how to stop my function with the mouse and restart it with the mouse.

first here is my test code:

  <script type="text/javascript">

  function fadeEngine(x) {

  var total_divs=3; //setze hier die nummer der gewollten divs

                  var y=x;

                  if(x==total_divs) y=1; else y++;

                  $("#fade"+x).css("display","none");

                  $("#fade"+y).fadeIn("slow");

                  setTimeout('fadeEngine('+y+')',3000); //modifi alle 3000 miliseconds nen neuen div
          }

        fadeEngine(0); //Initialisation des Scripts

  </script>

<script type="text/javascript">
$(document).ready(function(){
/*
    $("#container").hover(function(){
            stop('mouse over');
    },function(){
            alert('mouse out');
    });
*/
/*
$("#container").hover(function()
   {
      $(this).stop().fadeTo("slow", 1.00);
   },
   function()
   {
      $(this).stop().fadeTo("fast", 0.50);
   });
*/



});

</script>
</head>
<body>

<div id="container" style="width:200px;height:200px;background:#afafaf;color:#red;">

    <div id="fade1">Content  one</div>
    <div id="fade2" style="display:none">Content  two</div>
    <div id="fade3" style="display:none">Content three</div>
</div>
    <div class="blocker">&nbsp;</div>
</body>
</html>

How can I do this to stop the fadeEngine function if im navigate through the contentdiv and start it if im navigate out of the div?

thanks for the help

0

javascript jquery

andrew Dec 18 '08 at 12:00

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4 answers

geocar · Answer 1 · 2008-12-18T13:29:03+0000

Give all your #fade

X elements a class (say .faders) and then use:

$('.faders').stop();

Or give the container a div id like #faderbox

and say:

$('#faderbox div').stop();

Adam bellaire · Answer 2 · 2008-12-18T12:28:46+0000

I'm not sure exactly what you want to do with the fadeIn and fadeOut effects in your fadeEngine, however I can give you two tips:

You can use jQuery effect stop()

to stop all current jQuery animations for selected elements. For example:

$("#fade"+y).stop();

Will stop the fade animation for this element in its current state. You can reset the CSS if you like.

To stop calling a function that you previously queued with setTimeout

, you must get the return value and call clearTimeout()

. For example:

var timeout = setTimeout('fadeEngine('+y+')',3000);
// later...
clearTimeout(timeout);

This will clear the wait event and prevent it from appearing.

jp gorman · Answer 3 · 2008-12-18T13:03:30+0000

If this is just a case of attaching an animation to the mouse over bevahiour, etc., try this:

$(this).mouseover(function () {

    // stops the hide event if we move from the trigger to the popup element
    if (hideDelayTimer) clearTimeout(hideDelayTimer);

    // don't trigger the animation again if we're being shown, or already visible
    if (beingShown || shown) {
      return;
    } else {
      beingShown = true;

      // (we're using chaining) now animate
      this.animate({
        //some animation stuff
      }, function() {
      // once the animation is complete, set the tracker variables
        beingShown = false;
        shown = true;
      });
    }
}).mouseout(function () {

    // reset the timer if we get fired again - avoids double animations
    if (hideDelayTimer) clearTimeout(hideDelayTimer);

     // store the timer so that it can be cleared in the mouseover if required
    hideDelayTimer = setTimeout(function () {
      hideDelayTimer = null;
      this.animate({
         //some animation stuff
      }, function () {
      // once the animate is complete, set the tracker variables
        shown = false;
         });
      }, hideDelay);
});

jp gorman · Answer 4 · 2008-12-18T14:59:39+0000

Try to apply the break behavior to every element that requires it, eg.

$('.faders').each(function () {
  $(this).mouseover(function () {
    $(this).stop(); 
  });
});

Stop jQ animation

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