Clever Geek Handbook

Create single permutation with LINQ in C #

I have this code:

List<int> list = new List<int>();
for (int i = 1; i <= n; i++)
    list.Add(i);

Can I create this List<int>

in one line using LINQ?

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3 answers 


List<int> list = Enumerable.Range(1, n).ToList();


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List<int> list = Enumerable.Range(1, n).ToList();


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If you need a lot of these lists, you can find the following extension method:

public static class Helper
{
    public static List<int> To(this int start, int stop)
    {
        List<int> list = new List<int>();
        for (int i = start; i <= stop; i++) {
            list.Add(i);
        }
        return list;
    }
}

Use it like this:

var list = 1.To(5);

Of course, for the general case, the enumerated thing others have posted might be more than what you want, but I thought I'd share it;) You can use that next time your ruby-loving colleague speaks like verbose C # with this Enumerable.Range.

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