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Including PHP in weird with multiple inclusion

I have the following code:

if (include_once(dirname(__FILE__).'/file.php')
    || include_once(dirname(__FILE__).'/local/file.php')
    )
{

This raises an error as PHP is trying to include "1"

(presumably dirname(__FILE__).'/file.php' || dirname(__FILE__).'/local/file.php'

)

By commenting out the second line, this job works as intended, except it won't use the second file. Do I really need to use elseif

and duplicate the code here, or is there a way to get this to work?

$ php --version
PHP 5.2.6-3ubuntu4.2 with Suhosin-Patch 0.9.6.2 (cli) (built: Aug 21 2009 19:14:44)
Copyright (c) 1997-2008 PHP Group
Zend Engine v2.2.0, Copyright (c) 1998-2008 Zend Technologies

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2 answers


Group operators include

:

if ( (include_once dirname(__FILE__).'/file.php')
      ||
     (include_once dirname(__FILE__).'/local/file.php')
   )


See example # 4 on the man page:

<?php
// won't work, evaluated as include(('vars.php') == 'OK'), i.e. include('')
if (include('vars.php') == 'OK') {
    echo 'OK';
}

// works
if ((include 'vars.php') == 'OK') {
    echo 'OK';
}
?>
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Try using parentheses to subordinate operator precedence.



if ( (include_once('xml.php')) || (include_once('xml.php')) ) {
    echo 'bah';
}
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