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Passing multiple PHP parameters from Javascript

I am trying to use this

function GetXmlHttpObject()
{
if (window.XMLHttpRequest)
  {
  // code for IE7+, Firefox, Chrome, Opera, Safari
  return new XMLHttpRequest();
  }
if (window.ActiveXObject)
  {
  // code for IE6, IE5
  return new ActiveXObject("Microsoft.XMLHTTP");
  }
return null;
}

function CallSomePHP()
{
    xmlhttp=GetXmlHttpObject();
    if (xmlhttp==null)
    {
    alert ("Browser does not support HTTP Request");
    return;
    }
    var url="myPhp.php"; ***(Need to Pass multiple parameter to php from here)***
    xmlhttp.onreadystatechange=stateChanged;
    xmlhttp.open("GET",url,true);
    xmlhttp.send(null);
}

function stateChanged()
{
    if (xmlhttp.readyState==4)
    {
        alert(xmlhttp.responseText);
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2 answers


It's very simple:

var url="myPhp.php?param1="+ param1 + "&param2=" + param2

However, you can use jQuery.



How it got even easier;)

To have a full ajax call, you only need one method call, not worrying about browser issues. This makes your code much easier to read.

 $.ajax({
   // you can use post and get:
   type: "POST",
   // your url
   url: "some.php",
   // your arguments
   data: {name : "John", location : "Boston"},
   // callback for a server message:
   success: function( msg ){
     alert( "Data Saved: " + msg );
   },
   // callback for a server error message or a ajax error
   error: function( msg )
   {
     alert( "Data was not saved: " + msg );
   }
 });
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You add them to the url string, so:

var url="myPhp.php?a=1&b=2&c=3";


then you can access them in PHP from the $ _GET array:

$Param1 = $_GET['a']; // = 1
$Param2 = $_GET['b']; // = 2
$Param3 = $_GET['c']; // = 3
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