Is there a way to call a base class method of an object that overstates? (C ++)

Question

Is there a way to call a base class method of an object that overstates? (C ++)

I know some languages allow this. Is this possible in C ++?

+2

Scott 25 oct. '09 at 2:19

3 answers

class A
{
  virtual void foo() {}
};

class B : public A
{
   virtual void foo()
   {
     A::foo();
   }
};

+2

Paul lalonde 25 oct. '09 at 2:27

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Yes, just specify the type of the base class.

For example:

#include <iostream>

struct Base
{
    void func() { std::cout << "Base::func\n"; }
};

struct Derived : public Base
{
    void func() { std::cout << "Derived::func\n"; Base::func(); }
};

int main()
{
    Derived d;
    d.func();
}

+1

janm 25 oct. '09 at 2:25

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Martin York · Accepted Answer · 2009-10-25T02:24:40+0000

Yes:

#include <iostream>

class X
{
    public:
        void T()
        {
            std::cout << "1\n";
        }
};

class Y: public X
{
    public:
        void T()
        {
            std::cout << "2\n";
            X::T();             // Call base class.
        }
};


int main()
{
    Y   y;
    y.T();
}

Is there a way to call a base class method of an object that overstates? (C ++)

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