How to call methods with reference variables with expression trees
I am trying to figure out how to create an expression that calls a method that has a reference parameter.
Let me explain my question with a simple (but artificial) example. Consider the method:
public static int TwiceTheInput(int x)
{
return x*2;
}
I can create an expression to call the above method by doing something like:
{
var inputVar = Expression.Variable(typeof (int), "input");
var blockExp =
Expression.Block(
new[] {inputVar}
, Expression.Assign(inputVar, Expression.Constant(10))
, Expression.Assign(inputVar, Expression.Call(GetType().GetMethod("TwiceTheInput", new[] { typeof(int) }), inputVar))
, inputVar
);
var result = Expression.Lambda<Func<int>>(blockExp).Compile()();
}
When executed, the "result" above should be 20. Now let's look at a version of TwiceTheInput () that uses link parameters:
public static void TwiceTheInputByRef(ref int x)
{
x = x * 2;
}
How can I write a similar expression tree to call TwiceTheInputByRef () and pass arguments by reference?
Solution: (Thanks to Cicada). Using:
Type.MakeByRefType()
Here's a segment of code for generating an expression tree:
{
var inputVar = Expression.Variable(typeof(int), "input");
var blockExp =
Expression.Block(
new[] { inputVar }
, Expression.Assign(inputVar, Expression.Constant(10))
, Expression.Call(GetType().GetMethod("TwiceTheInputByRef", new[] { typeof(int).MakeByRefType() }), inputVar)
, inputVar
);
var result = Expression.Lambda<Func<int>>(blockExp).Compile()();
}
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You don't need to change much, just delete Assign
and change typeof(int)
to typeof(int).MakeByRefType()
.
var blockExp = Expression.Block(
new[] { inputVar }
, Expression.Assign(inputVar, Expression.Constant(10))
, Expression.Call(
typeof(Program).GetMethod(
"TwiceTheInputByRef", new [] { typeof(int).MakeByRefType() }),
inputVar)
, inputVar
);
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