ViewWithTag in UICollectionViewCell returns nil in Swift (until cell is reused)

This long title is roughly my problem. I started a simple learning example using UICollectionView in a Swift project.

I added a CollectionView to a ViewController created with a template, assigned delegate and datasource. A custom cell is created in the storyboard. Reuse ID is set.

Everything is fine so far. I put one UILabel in a custom cell and gave the tag value 100.

Here's the code of my ViewController: https://gist.github.com/tomekc/becfdf6601ba64d5fd5d

And an interesting exceprt below:

func collectionView(collectionView: UICollectionView!, cellForItemAtIndexPath indexPath: NSIndexPath!) -> UICollectionViewCell! {
        let cell = collectionView.dequeueReusableCellWithReuseIdentifier("element", forIndexPath: indexPath) as UICollectionViewCell

        cell.backgroundColor = UIColor.yellowColor()

        // list subviews
        NSLog("--- ROW %d ---", indexPath.row)
        printSubviews(cell)

        if let labelka = cell.viewWithTag(100) as? UILabel {
            labelka.text = String(format: "Row %d", indexPath.row)
            NSLog("Found label")
        }


        return cell
    }


    func printSubviews(view:UIView) {
        if let list = view.subviews as? [UIView] {
            for uiv in list {
                NSLog("%@ tag:%d", uiv, uiv.tag)
                printSubviews(uiv)
            }
        }
    }

      

        
        
        
      

    

The problem is that it cell.viewWithTag(100)

returns nil until the cell is reused . When I scroll through the view, so any of the cells exits the window, and reuse is forced, it viewWithTag(100)

returns the label and I can set its value.

Interestingly, I put together a similar example in Objective-C and there is no such problem. Even when building and running with XCode6 beta4.

I wonder if I missed something or is this wrong behavior?

Update: Apparently I used an overly simplistic approach. When I created my own UICollectionViewCell subclass (as I usually do), the result is correct.