Regex only captures the first match

Question

I have searched for searches and looked at the recommended question suggested by Stack Overflow. However, I was unable to find the answers.

I want to parse a string using regex, an example string is

Lot: He said: Thou shalt not pass!

I want to capture Lot

both a group and He said: Thou shalt not pass!

. However, when I used my template (.+): (.+)

, it returns

Lot: He said:

and Thou shalt not pass!

Can it be written He said: Thou shalt not pass

with regex?

+3

Wancak terakhir 01 Sep '14 at 9:34

5 answers

try:

([^:]+):\s*(.*)

+3

Kent 01 Sep '14 at 9:36 am

(?=.*?:.*?:)(.*?):(.*)

You can use this.

See demo.

+2

vks 01 Sep '14 at 9:37

The following work is in progress.

([^:]+): (.+)

+1

Venky 01 Sep '14 at 9:44

You must use the flags ig - i = case insensitive, g = do not return after the first match, and an expression like "(. :)? (.:. *)".

+1

Matheus dadalto Sep 25 '17 at 9:21

sp00m · Accepted Answer · 2014-09-01T09:36:12+0000

For the first group you need non-greedy (or lazy) power: (.+?): (.+)

.

Read more about http://www.regular-expressions.info/repeat.html chapter "Laziness instead of greed".