Django template template
{% with start=0 end=entries.number|add:"2" %}
{{ paginator.page_range|slice:"start:end" }}
{{ start }}, {{ end }}
{{ paginator.page_range|slice:"0:3" }}
{% endwith %}
Why is the Django 1.5 templating engine producing the following output for the above code:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
0, 3
[1, 2, 3]
0
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1 answer
How about using code, Luke?
https://github.com/django/django/blob/master/django/template/defaultfilters.py
@register.filter("slice", is_safe=True)
def slice_filter(value, arg):
"""
Returns a slice of the list.
Uses the same syntax as Python list slicing; see
http://www.diveintopython3.net/native-datatypes.html#slicinglists
for an introduction.
"""
try:
bits = []
for x in arg.split(':'):
if len(x) == 0:
bits.append(None)
else:
bits.append(int(x))
return value[slice(*bits)]
except (ValueError, TypeError):
return value # Fail silently.
In short: the filter does not have access to the context, so it cannot resolve variables and only works on literal values.
+1
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