How to take nth order discrete sum from numpy array (total numpy.diff equivalent)

I know it is possible to take the nth order discrete difference of a numpy array using the numpy function numpy.diff()

, but is there a way to do the same with nth order discrete sum?

Let's say we have an array of numpy, A = np.arange(10)

. Expected output for 1st order discrete sum:

array([  1.,   3.,   5.,   7.,   9.,  11.,  13.,  15.,  17.]) 

      

        
        
        
      

    

which i can get:

N = A.shape[0]
B = np.zeros(N-1)

for i in range(N-1):
    B[i] = A[i+1] + A[i]

      

        
        
        
      

    

But is there a function to avoid using a for loop?