Regex to find at least 4 occurrences of a forward slash in a string

Question

I have some urls and I would like to make sure they have at least 4 slashes as some of my urls have less. For example:

Any help would be much appreciated. thanks to Dave

+3

dave May 28 '15 at 22:26

3 answers

Use a lookahead like:

^(?=(?:[^\/]*\/){4,})(.*)

0

dawg May 28 '15 at 11:41 pm

Just compare it 4 times:

(?:.*?/){4}

The reluctance quantifier *?

ensures that trailing slashes are not skipped in matching (excluding trail tracking)

_{Your regex engine (undefined) may require escaping forward slashes, i.e. \/}

0

Bohemian May 28 '15 at 23:53

apgp88 · Accepted Answer · 2015-05-28T22:33:36+0000

You can try the following regex,

\/\/(.*\/){3}