How to deal with multiple publishers on one port in zmq?

This question was asked earlier, here . I have exactly the same problem. I want to publish from many different processes and use the same port every time.

I tried the solution provided in the answer, but it didn't work for me. I get an error

    File "/usr/local/lib/python2.7/multiprocessing/process.py", line 258, in _bootstrap
    self.run()
  File "/usr/local/lib/python2.7/multiprocessing/process.py", line 114, in run
    self._target(*self._args, **self._kwargs)
  File "/home/akay/afk/multi.py", line 18, in to_zmq
    socket.connect("tcp://*:%s" % port)
  File "zmq/backend/cython/socket.pyx", line 478, in zmq.backend.cython.socket.Socket.connect (zmq/backend/cython/socket.c:4308)
ZMQError: Invalid argument

      

        
        
        
      

    

My code is similar to this, essentially straight from the example in the zmq docs here and here :

# Socket to talk to server
port = '5556'
context = zmq.Context()
socket = context.socket(zmq.SUB)
print "Listening for stream...", m
socket.bind("tcp://localhost:%s" % port) #change connect to bind, as per answer above
socket.setsockopt(zmq.SUBSCRIBE, topicfilter)

      

        
        
        
      

    

I am using python 2.7 and latest zmq. Any idea what I might be doing wrong?