How to read numbers of n lines into a Scala list?

Question

This is for the online judge. I am trying to learn some Scala in the process.

The input format looks like

So the first line is n, and then the next n lines contain the items to go to the list.

Right now I'm reading n using readInt()

, but I don't know how to say, "Now read the next n lines and put everything in a list."

+3

Sean hill 08 june 15 at 14:05

2 answers

This can be done on one line if you trust this input and ignore this first range value.

val list = io.StdIn.getLines.drop(1).map(_.toInt).toList

0

Ben che 08 june 15 at 16:49

integer-j · Accepted Answer · 2015-06-08T14:43:59+0000

Try the following:

val n = io.StdIn.readInt
val list = ( 0 to n ).map( (x) -> io.StdIn.readLine ).toList
//...