RegExp in PHP. Get text between first level brackets
I have two types of lines in one text:
a (bc) de (fg) h
a (BCD (eff) d) h
I need to get the text between the first level brackets. In my example, this is:
Bc
fg
BCD (eff) g
I tried using the following regex /\((.+)\)/
with the Ungreedy (U) flag:
Bc
fg
BCD (eff
And without it:
Bc) de (fg
BCD (eff) g
Both options don't do what I need. Maybe someone knows how to solve my problem?
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Use PCRE Recursive Pattern to Match Substrings in Nested Parentheses:
$str = "a(bc)de(fg)h some text a(bcd(ef)g)h ";
preg_match_all("/\((((?>[^()]+)|(?R))*)\)/", $str, $m);
print_r($m[1]);
Output:
Array
(
[0] => bc
[1] => fg
[2] => bcd(ef)g
)
\( ( (?>[^()]+) | (?R) )* \)
It first matches the open parenthesis. It then matches any number of substrings, which can be either a sequence without parentheses, or a recursive match on the pattern itself (i.e., a correctly parenthesized substring). Finally, there is a closing parenthesis.
Technical Precautions:
If the pattern contains more than 15 parentheses, PCRE uses pcre_malloc to get additional memory to store data during recursion, then frees it with pcre_free. If no memory can be obtained, it stores the data for the first 15 captures only in parentheses, since there is no way to throw an out-of-memory error from within the recursion.
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Please can you try the following:
preg_match("/\((.+)\)/", $input_line, $output_array);
Check out this code at http://www.phpliveregex.com/
Regex: \((.+)\)
Input: a(bcd(eaerga(er)gaergf)g)h
Output: array(2
0 => (bcd(eaerga(er)gaergf)g)
1 => bcd(eaerga(er)gaergf)g
)
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