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How to apply an XSL template only to elements containing a child element with a specific attribute value and element value?

I have the following XML (partial) document:

<export>
<table name="CLIENT">
    <row>
        <col name="CODE_CLIENT" type="System.String">1000010026</col>
       <col name="LIBELLE" type="System.String">Test|</col>
        <col name="PROSPECT" type="System.Decimal">1</col>
    </row>
    <row>
        <col name="CODE_CLIENT" type="System.String">1000010025</col>
        <col name="LIBELLE" type="System.String">Rue de la 2eme ad|</col>
        <col name="PROSPECT" type="System.Decimal">0</col>
    </row>
    <row>
        <col name="CODE_CLIENT" type="System.String">1000010125</col>
       <col name="LIBELLE" type="System.String">Test4</col>
        <col name="PROSPECT" type="System.Decimal">0</col>
    </row>
    <row>
        <col name="CODE_CLIENT" type="System.String">1000010035</col>
        <col name="LIBELLE" type="System.String">Rue</col>
        <col name="PROSPECT" type="System.Decimal">1</col>
    </row>
    </table></export>

and the following XSL:

<xsl:stylesheet version="1.1" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output method="text" indent="yes"/>

  <xsl:template match="/">
    <xsl:apply-templates select="export/table[@name='CLIENT']"/>

  </xsl:template>

  <xsl:template match="row">
        SOME TEMPLATE CODE

  </xsl:template>


</xsl:stylesheet>

I would like to apply the first pattern (match = "/") only to "strings" that have a perspective value of 1. In my example, this will only transform the first and last strings.

I tried

<xsl:apply-templates select="export/table[@name='CLIENT']/row[col[@name='PROSPECT']=1]"/>

but that gave me a syntax error.

Does anyone know how to proceed?

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4 answers


My suggestion:

<xsl:stylesheet 
  version="1.1" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>
  <xsl:output method="text" indent="yes"/>

  <xsl:template match="/">
    <xsl:apply-templates select="export/table[@name='CLIENT']"/>
  </xsl:template>

  <xsl:template match="table">
    <xsl:apply-templates select="row[col[@name='PROSPECT' and text() = '1']]" />
  </xsl:template>

  <xsl:template match="row">
    SOME TEMPLATE CODE
  </xsl:template>

</xsl:stylesheet>

While your attempt:



<xsl:apply-templates select="
  export/table[@name='CLIENT']/row[col[@name='PROSPECT']=1]
"/>

should work too (it's not that obvious, but it's not in itself). Not sure why this doesn't work for you.

+2


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Caution: untested. Perhaps he didn't even get it right.



<xsl:template match="row[string(./col[@name='PROSPECT']) = '1']">

</xsl:template>
0


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I tried your application templates and it did not disappoint. Are you sure there is a bug in the Apply templates?

0


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<xsl:apply-templates select="export/table[@name='CLIENT']/row/col[text()='1' and @name='PROSPECT']"/>
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