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Windows Forms PictureBox - how to display an image in a specific area of ​​a form

I am using the following code to open and display an image in one of my forms with fileDialog

:

private void btnExplorer_Click(object sender, EventArgs e)
        {
            OpenFileDialog openFileDialog1 = new OpenFileDialog();

            openFileDialog1.InitialDirectory = "c:\\";
            openFileDialog1.Filter = "All files (*.*)|*.*";
            openFileDialog1.FilterIndex = 2;
            openFileDialog1.RestoreDirectory = true;

            if (openFileDialog1.ShowDialog() == DialogResult.OK)
            {
                try
                {
                    PictureBox PictureBox1 = new PictureBox();
                    PictureBox1.Image = new Bitmap(openFileDialog1.FileName);
                    // Add the new control to its parent controls collection
                    this.Controls.Add(PictureBox1);
                }
                catch (Exception ex)
                {
                    MessageBox.Show("Error loading image" + ex.Message);
                }
            }
        }

The problem is that my image appears in the upper left corner of my form when I left almost a quarter of my right side for this purpose. How can I show it there?

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2 answers


As I said in my comment, here's how: How to manage positions in Windows formats .

PictureBox PictureBox1 = new PictureBox();
PictureBox1.Image = new Bitmap(openFileDialog1.FileName);
PictureBox1.Location = new Point(20, 100); //20 from left and 100 from top
this.Controls.Add(PictureBox1);


Or change it later:

PictureBox1.Top += 50; //increase distance from top with 50
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You can set the location property for the PictureBox before adding it to the parent.



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