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Get numbers after php regex string

I need a regex that can actually get any number that is inserted after "ab" and "cr". For example, I have a line like this:

rw200-208-ab66
fg200-cr30-201

I need to print ab66

and cr30

.

I tried using strpos

:

if (strpos($part,'ab') !== false) {
            $a = explode("ab", $part);
           echo 'ab'.$a[1];
    }

It doesn't work for the second item.

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2 answers


Use this regex:

(?>ab|cr)\d+

See IDEONE demo :



$re = "#(?>ab|cr)\d+#"; 
$str = "rw200-208-ab66\nfg200-cr30-201"; 
preg_match_all($re, $str, $matches);
print_r($matches[0]);

Output:

Array
(
    [0] => ab66
    [1] => cr30
)
+2


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You can use \K

to discard previously matched characters from being printed in the final. Below regex will give you the number that exists next to ab

 or cr

.

(?:ab|cr)\K\d+


To get a number with alphabets use

preg_match_all('~(?:ab|cr)\d+~', $str, $match);
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